【smtp】smtp发送带附件的邮件代码分享-发送-带附件的邮件

欢迎您访问我爱IT技术网，今天小编为你分享的编程技术是：【smtp发送带附件的邮件代码分享】，下面是详细的讲解！

smtp发送带附件的邮件代码分享

public static void sendEmail(string toAddress, string emailbody)
{
var fromAddress=ConfigurationManager.AppSettings["EmailAddress"];
string fromPassword=ConfigurationManager.AppSettings["EmailPassword"].ToString();
const string subject="Job Recommendation";
var smtp=new SmtpClient
{
Host=ConfigurationManager.AppSettings["SmtpServer"].ToString(),
Port=int.Parse(ConfigurationManager.AppSettings["SmtpPort"]),
EnableSsl=true,
DeliveryMethod=SmtpDeliveryMethod.Network,
UseDefaultCredentials=false,
Credentials=new NetworkCredential(fromAddress, fromPassword)
};
using (var message=new MailMessage(fromAddress, toAddress, subject, HttpUtility.HtmlEncode(emailbody)))
{
smtp.Send(message);
}
}
<add key="EmailAddress" value="**********@gmail.com"/>//Email Address
<add key="EmailPassword" value="*********"/> //Emial PWD
<add key="SmtpServer" value="smtp.gmail.com"/>
<add key="SmtpPort" value="587"/>
<--带附件版本->
var fromAddress="allenyinj@gmail.com";
string fromPassword="yj1989120";
const string subject="CV";
var smtp=new SmtpClient
{
Host="smtp.gmail.com",
Port=587,
EnableSsl=true,
DeliveryMethod=SmtpDeliveryMethod.Network,
UseDefaultCredentials=false,
Credentials=new NetworkCredential(fromAddress, fromPassword)
};
MailMessage email=new MailMessage(fromAddress, "allen.yin.jun@gmail.com");
email.Subject="INLINE attachment TEST";
email.IsBodyHtml=true;
string attachmentPath="C:\\3.jpeg";
Attachment inline=new Attachment(attachmentPath);
inline.ContentDisposition.Inline=true;
inline.ContentDisposition.DispositionType=DispositionTypeNames.Inline;
//inline.ContentId="1";
//inline.ContentType.MediaType="image/png";
inline.ContentType.Name=Path.GetFileName(attachmentPath);
email.Attachments.Add(inline);
email.Body="test";
smtp.Send(email);
email.Dispose();
//如果没有路径，用Stream
Attachment letter=new Attachment(FileUploadLetter.FileContent, FileUploadLetter.PostedFile.ContentType);
letter.ContentDisposition.Inline=true;
letter.ContentDisposition.DispositionType=DispositionTypeNames.Inline;
//inline.ContentId="1";
letter.ContentType.MediaType=FileUploadLetter.PostedFile.ContentType;
letter.ContentType.Name=Path.GetFileName(FileUploadLetter.PostedFile.FileName);
letter.Name=Path.GetFileName(FileUploadLetter.PostedFile.FileName);

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